(x^3)-((3x^2)y)+(2xy^2)=12

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Solution for (x^3)-((3x^2)y)+(2xy^2)=12 equation:


Simplifying
(x3) + -1((3x2) * y) + (2xy2) = 12
x3 + -1((3x2) * y) + (2xy2) = 12

Remove parenthesis around (3x2)
x3 + -1(3x2 * y) + (2xy2) = 12

Multiply x2 * y
x3 + -1(3x2y) + (2xy2) = 12

Remove parenthesis around (3x2y)
x3 + -1 * 3x2y + (2xy2) = 12

Multiply -1 * 3
x3 + -3x2y + (2xy2) = 12

Reorder the terms:
(2xy2) + -3x2y + x3 = 12

Solving
(2xy2) + -3x2y + x3 = 12

Solving for variable 'x'.

Reorder the terms:
-12 + (2xy2) + -3x2y + x3 = 12 + -12

Combine like terms: 12 + -12 = 0
-12 + (2xy2) + -3x2y + x3 = 0

The solution to this equation could not be determined.

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